1-(0.95)^n >= 0.95 =〉n >= 59 是怎么计算出来的？要计算过程

1-(0.95)^n >= 0.95
0.95^n<=0.05
y=0.95^n是减函数
当n=log(0.95)0.05时
0.95^n=0.05
所以n>=log(0.95)0.05
log(0.95)0.05约等于58.4
所以如果n是整数的话
n>=59

1-(0.95)^n >= 0.95

0.95^n<=1-0.95=0.05

lg0.95^n<=lg0.05

nlg0.95<=lg0.05

n>=lg0.05/lg0.95=-1.301/(--0.022)=58.4

即:n>=59

-0.95^n>=-0.05
0.95^n<=0.05
n<=0.05^(1/0.95)
1/0.95=100/95=20/19
n<=0.05^(20/19)